# How much zinc is required to react with excess hydrochloric acid to produce 5.6 liters of hydrogen?

July 25, 2021 | education

| Zinc metal reacts with hydrochloric (hydrochloric) acid to release hydrogen gas and form zinc chloride. The reaction is described by the following equation:

Zn + 2HCl = ZnCl2 + H2;

1 mole of metal reacts with 2 moles of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the released amount of hydrogen. To do this, we divide the volume of synthesized hydrogen by the volume of 1 mole of gas, which is 22.4 liters.

V H2 = 5.6 liters; N H2 = 5.6 / 22.4 = 0.25 mol;

To synthesize such an amount of hydrogen, it is necessary to take the same amount of zinc. Let’s calculate its weight.

M Zn = 65 grams / mol;

m Zn = 0.25 x 65 = 16.25 grams;

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