How much zinc is required to react with excess hydrochloric acid to produce 5.6 liters of hydrogen?
July 25, 2021 | education
| Zinc metal reacts with hydrochloric (hydrochloric) acid to release hydrogen gas and form zinc chloride. The reaction is described by the following equation:
Zn + 2HCl = ZnCl2 + H2;
1 mole of metal reacts with 2 moles of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.
Let’s calculate the released amount of hydrogen. To do this, we divide the volume of synthesized hydrogen by the volume of 1 mole of gas, which is 22.4 liters.
V H2 = 5.6 liters; N H2 = 5.6 / 22.4 = 0.25 mol;
To synthesize such an amount of hydrogen, it is necessary to take the same amount of zinc. Let’s calculate its weight.
M Zn = 65 grams / mol;
m Zn = 0.25 x 65 = 16.25 grams;
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