How much zinc should be taken for the reaction with hydrochloric acid, if 270 g of zinc chloride should be formed

How much zinc should be taken for the reaction with hydrochloric acid, if 270 g of zinc chloride should be formed as a result of the reaction.

The equation:
Zn + 2HCl = ZnCl2 + H2
M (ZnCl2) = 65 + 35.5 * 2 = 136 g / mol
n (ZnCl2) = 270/136 = 2 mol
n (ZnCl2) = n (Zn) = 2 mol
m (Zn) = 65 * 2 = 130 g



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