How to change the frequency of oscillations in the electrical circuit if the capacitance of the capacitor increases
How to change the frequency of oscillations in the electrical circuit if the capacitance of the capacitor increases by 2 times, and the inductance of the coil decreases by 8 times?
Given:
L2 = L1 / 8 ratio of the inductances of the coils;
C2 = 2C1 is the ratio of the capacitances of the capacitors.
Find: the ratio of the oscillation frequency of the circuits.
Let’s use the formula for the frequency of oscillations in the circuit.
n = 1 / (2 * Π * √ (L * C)); where L is the inductance of the coil, C is the capacitance of the capacitor.
n2 = 1 / (2 * Π * √ ((L1 / 8) * 2C1)) = 1 / (2 * Π * √ ((L1 * C1) / 4) =
= 1 / (2 * Π * 1/2 * √ (L1 * C1) = 2 * 1 / (2 * Π * 1/2 * √ (L1 * C1) = 2n1.
Answer: the frequency of oscillations in the electrical circuit will increase by 2 times.