How to determine the force of gravity acting on a body weighing 3.5 kg; 400 grams; 1.5 tons; 60 grams.

Given:

m1 = 3.5 kilograms – the mass of the first body;

m2 = 400 grams = 0.4 kilograms – the mass of the second body;

m3 = 1.5 tons = 1500 kilograms – the mass of the third body;

m4 = 60 grams = 0.06 kilograms – the mass of the fourth body;

g = 9.8 m / s ^ 2 – acceleration of gravity.

It is required to determine the gravity forces acting on bodies F1, F2, F3, F4 (Newton).

F1 = m1 * g = 3.5 * 9.8 = 34.3 Newton.

F2 = m2 * g = 0.4 * 9.8 = 3.92 Newton.

F3 = m3 * g = 1500 * 9.8 = 14700 Newton.

F4 = m4 * g = 0.06 * 9.8 = 0.588 Newton.

Answer: the force of gravity acting on the first body is 34.3 Newton, on the second body 3.92 Newton, on the third body 14700 Newton, on the fourth body 0.588 Newton.



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