How to determine the force of gravity acting on a body weighing 3.5 kg; 400 grams; 1.5 tons; 60 grams.
September 28, 2021 | education
| Given:
m1 = 3.5 kilograms – the mass of the first body;
m2 = 400 grams = 0.4 kilograms – the mass of the second body;
m3 = 1.5 tons = 1500 kilograms – the mass of the third body;
m4 = 60 grams = 0.06 kilograms – the mass of the fourth body;
g = 9.8 m / s ^ 2 – acceleration of gravity.
It is required to determine the gravity forces acting on bodies F1, F2, F3, F4 (Newton).
F1 = m1 * g = 3.5 * 9.8 = 34.3 Newton.
F2 = m2 * g = 0.4 * 9.8 = 3.92 Newton.
F3 = m3 * g = 1500 * 9.8 = 14700 Newton.
F4 = m4 * g = 0.06 * 9.8 = 0.588 Newton.
Answer: the force of gravity acting on the first body is 34.3 Newton, on the second body 3.92 Newton, on the third body 14700 Newton, on the fourth body 0.588 Newton.
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