# How to determine the force of gravity acting on a body weighing 3.5 kg; 400 grams; 1.5 tons; 60 grams.

Given:

m1 = 3.5 kilograms – the mass of the first body;

m2 = 400 grams = 0.4 kilograms – the mass of the second body;

m3 = 1.5 tons = 1500 kilograms – the mass of the third body;

m4 = 60 grams = 0.06 kilograms – the mass of the fourth body;

g = 9.8 m / s ^ 2 – acceleration of gravity.

It is required to determine the gravity forces acting on bodies F1, F2, F3, F4 (Newton).

F1 = m1 * g = 3.5 * 9.8 = 34.3 Newton.

F2 = m2 * g = 0.4 * 9.8 = 3.92 Newton.

F3 = m3 * g = 1500 * 9.8 = 14700 Newton.

F4 = m4 * g = 0.06 * 9.8 = 0.588 Newton.

Answer: the force of gravity acting on the first body is 34.3 Newton, on the second body 3.92 Newton, on the third body 14700 Newton, on the fourth body 0.588 Newton. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.