How to find AB if ABC triangle angle C = 90 degrees BC = 2 sinA = 0’4.

In a right-angled triangle, the sine of the angle is equal to the ratio of the opposite side to the hypotenuse. AB in this triangle is the hypotenuse, since the angle C is right. Opposite corner A lies side BC, therefore sinA = BC / AB. That is, AB = BC / sinA = 2 / 0.4 = 5.



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