How to find the acceleration from the coordinate equation x = x0 + 3t + t ^ 2 (squared)?
| February 1, 2021 | education
x (t) = x0 + 3 * t + t ^ 2.
and – ?
The first derivative of the dependence of the coordinate of motion on time x (t) “will be the dependence of the speed of motion on time V (t): V (t) = x (t)”.
The second derivative of the dependence of the coordinate of motion on time x (t) “” will be the dependence of acceleration on time a (t): a (t) = x (t) “” = V (t) “.
V (t) = (x0 + 3 * t + t ^ 2) “= 3 + 2 * t.
a (t) = (3 + 2 * t) “= 2.
Answer: the body moves with a constant acceleration a = 2 m / s ^ 2.
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