How to find the area of a rhombus if the diagonals 4 and 6 are known.

The diagonals of the rhombus, at the point of intersection, are halved and divide the rhombus into four equal, right-angled triangles.

AO = AC / 2 = 6/2 = 3 cm, BO = BD / 2 = 4/2 = 2 cm.

Savsd = 4 * Saov = 4 * (AO * ВO) / 2 = 4 * 3 * 2/2 = 12 cm2.

Answer: The area of the rhombus is 12 cm2.



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