How to find the mass of copper obtained during the reduction of copper oxide and hydrogen, with a volume of 11.2 liters.

univerkov | January 17, 2021 | education

Given:
V (H2) = 11.2 L
To find:
m (Cu)
Decision:
CuO + H2 = Cu + H2O
n (H2) = V / Vm = 11.2 L / 22.4 L / mol = 0.5 mol
n (H2): n (Cu) = 1: 1
n (Cu) = 0.5 mol
m (Cu) = n * M = 0.5 mol * 64 l / mol = 32 g
Answer: 32 g

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