How to find the perimeter of a triangle abc if sides AB and BC = 5cm and angle B = 60 degrees

1) triangle ABC is isosceles (because AB = BC = 5)
2) the angles at the base are equal (property of an isosceles triangle). angle A = B = (180-60): 2 = 60 degrees
3) if all angles are 60 degrees, then the triangle is equilateral
4) P = AB + BC + AC = 5 + 5 + 5 = 15 cm



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