How to find the volume of gas that was formed when processing 100 kg of limestone containing 15%

How to find the volume of gas that was formed when processing 100 kg of limestone containing 15% of non-carbonate impurities, treated with a sufficient amount of hydrochloric acid solution.

When calcium carbonate interacts with hydrochloric acid, calcium chloride, water is synthesized and gaseous carbon dioxide is released. The reaction proceeds according to the following chemical equation:

CaCO3 + 2HCl = CaCl2 + CO2 ↑ + H2O;

Let’s calculate the molar amount of calcium carbonate. To do this, divide its weight by its molar weight.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 100,000 x 0.85 / 100 = 850 mol;

850 mol of calcium carbonate will react with 850 x 2 = 1,700 mol of hydrochloric acid. This will release 850 mol of carbon dioxide.

Let’s find its volume. To this end, we multiply the amount of substance by the volume of 1 mole of gas (filling 22.4 liters).

V CO2 = 850 x 22.4 = 19,040 liters = 19.04 m3;