How to find the zeros of the function y = 5x ^ 2-7x + 2?

In the equation, we define the coefficients – the numbers in the quadratic equation ax ^ 2 + bx + c = 0.
a = 5, b = -7, c = 2.
To calculate the root, we need the discriminant formula:
D = b ^ 2 – 4ac = (-7) ^ 2 – 4 * 5 * 2 = 49 – 40 = 9.
D ^ (1/2) = 3.
Because D is greater than 0, then there are two roots, and they are found by the formula x = (-b ± D ^ (1/2)) / (2a).
x1 = (7 – 3) / (2 * 5) = 4/10 = 0.4.
x2 = (7 + 3) / (2 * 5) = 1.