How to obtain a Cu (NO3) 2 salt using a neutralization reaction?

For this we take an insoluble base Cu (OH) 2 and a strong acid HNO3. Our equation will look like this (do not forget to level): Cu (OH) 2 + 2HNO3 -> Cu (NO3) 2 + H2O. As a result of the exchange reaction, we got salt and water.



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