How to prove that all angles are equal in an equilateral triangle?

Let an equilateral triangle ABC be given, then AB = BC = AC. By the property of the angles at the base of the AC in the isosceles triangle ABC, we obtain that ∠BAC = ∠BCA. By the property of angles at the base of AB in an isosceles triangle ABC, we obtain that ∠BAC = ∠CAB. So, in this triangle ABC: ∠BAC = ∠BCA = ∠CAB. From this we can conclude that in an equilateral triangle, all angles are equal. Q.E.D.



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