How to prove that one of the two solutions contains Al ^ 3 + ions, and the other contains

How to prove that one of the two solutions contains Al ^ 3 + ions, and the other contains Ba ^ 2 + ions? write the equations of the reactions taking place.

Divide the contents of the solutions into 2 parts. Add alkali to one part, sulfuric acid to the other. A white precipitate will appear in both tubes.

A qualitative reaction to Al3 + ions is interaction with alkali, as a result of the reaction a white precipitate – Al (OH) 3 – aluminum hydroxide forms.

A qualitative reaction to Ba2 + ions is the interaction with sulfate – anions SO4 / 2-, as a result of the reaction a white precipitate – BaSO4 – barium sulfate precipitates.

To recognize which tube contains barium sulfate and which one contains aluminum hydroxide, add nitric acid to each tube.

Barium sulfate does not dissolve in acid. The aluminum hydroxide will dissolve.

Ва²⁺ + SO₄^2- = BaSO₄↓.

Al³⁺  + 3 OH^1-  = Al(OH)₃ ↓.

BaSO₄  + 2HNO₃ ↔Ba(NO₃)₂ + 2HNO₃

BaSO₄  + 2H¹⁺ + 2NO₃ ^1- ↔Ba²⁺ + 2NO₃ ^1-+ 2H ¹⁺ + 2 NO₃^1-