How to solve a system of linear equations for (x0, y0) the equation x + 2y = 4 and 3x-4y = 7

{x + 2y = 4, 3x – 4y = 7};
From the first equation of the system, we express the variable x and substitute it into the second equation of the system.
{x = 4 – 2y, 3 * (4 – 2y) – 4y = 7};
{x = 4 – 2y, 3 * 4 – 3 * 2y – 4y = 7};
{x = 4 – 2y, 12 – 6y – 4y = 7};
{x = 4 – 2y, 12 – 10y = 7};
{x = 4 – 2y, 10y = 12 – 7};
{x = 4 – 2y, 10y = 5};
{x = 4 – 2y, y = 5: 10};
{x = 4 – 2y, y = 0.2};
{x = 4 – 2 * 0.2, y = 0.2};
{x = 4 – 0.4, y = 0.2};
{x = 3.6, y = 0.2}.
Answer: x0 = 3.6; y0 = 0.2.