How will the amount of heat released by the electric stove spiral change when the current in the circuit doubles?

univerkov | February 5, 2021 | education

Given:

I2 = 2 * I1 – the current in the electrical circuit has doubled.

It is required to determine Q2 / Q1 – how the amount of heat released by the spiral of an electric stove will change when the current strength changes.

The amount of heat released in the first case will be equal to:

Q1 = U * I1 * t, where U is the voltage of the electrical network, t is the time interval.

The amount of heat released in the second case will be equal to:

Q2 = U * I2 * t = U * 2 * I1 * t = 2 * U * I1 * t.

Then:

U2 / U1 = (2 * U * I1 * t) / (U * I1 * t) = 2, that is, will increase by 2 times.

Answer: with an increase in the current strength by 2 times, the amount of heat released will also increase by 2 times.

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