How will the amount of heat released on the resistor change when the current strength is reduced by 2 times?

Given:

I2 = I1 / 2 – the current was reduced by 2 times;

It is required to determine Q2 / Q1 – how the amount of heat released on the resistor will change with decreasing current strength.

The amount of heat released in the first case will be equal to:

Q1 = U * I1 * t, where U is the voltage of the electrical network, t is the time interval.

The amount of heat released in the second case will be equal to:

Q2 = U * I2 * t = U * I1 * t / 2.

Then:

U2 / U1 = (U * I1 * t / 2) / (U * I1 * t) = 1/2, that is, will decrease by 2 times.

Answer: when the current strength is reduced by 2 times, the amount of heat released will also decrease by 2 times.