How will the Coulomb force of interaction of two identical point charges change if the value of one of the charges is increased threefold, and the other is reduced by three times?
q – two identical point charges;
q1 = 3 * q – the first charge was increased by 3 times;
q2 = q / 3 – the second charge was reduced by 3 times.
It is required to determine F2 / F1 – how the Coulomb interaction force of two charges will change when they change.
The force of interaction in the first case will be equal to:
F1 = k * q * q / r ^ 2 = k * q ^ 2 / r ^ 2, where k is an electrical constant, r is the distance between charges.
The force of interaction in the second case will be equal to:
F2 = k * q1 * q ^ 2 / r ^ 2 = k * 3 * q * (q / 3) / r2 = k * q ^ 2 / r ^ 2.
Since F1 = F2 (k * q ^ 2 / r ^ 2 = k * q ^ 2 / r ^ 2), the force of interaction will not change.
Answer: with the indicated change in charges, the force of their Coulomb interaction will not change.
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