How will the force of attraction between two bodies change if a) the distance between their centers is doubled

How will the force of attraction between two bodies change if a) the distance between their centers is doubled, b) the mass of each of the bodies is reduced by 3 times?

R1 = 2 * R.

m2 “= m2 / 3.

m1 “= m1 / 3.

F / F1 -?

F / F2 -?

According to the law of universal gravitation, the force F of attraction between bodies is determined by the formula: F = G * m1 * m2 / R ^ 2, where G is the gravitational constant, m1, m2 are the masses of interacting bodies, R is the distance between their centers.

F1 = G * m1 * m2 / R1 ^ 2 = G * m1 * m2 / (2 * R) ^ 2 = G * m1 * m2 / 4 * R ^ 2 = F / 4.

F2 = G * m1 “* m2” / R ^ 2 = G * m1 * m2 / 3 * 3 * R ^ 2 = G * m1 * m2 / 9 * R ^ 2 = F / 9.

Answer: with an increase in the distance by 2 times, the force will decrease by 4 times: F / F1 = 4. With a decrease in the mass of two bodies by 3 times, the force will decrease by 9 times: F / F2 = 9.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.