How will the force of gravity between two bodies change if the distance between them is increased by 3 times?

R2 = 3 * R1.
F1 / F2 -?
According to the law of universal gravitation: the force of interaction F between two bodies of mass m1 and m2, which are at a distance R, is determined by the formula: F = G * m1 * m2 / R ^ 2. Where G is the gravitational constant.
F1 = G * m1 * m2 / R1 ^ 2.
F2 = G * m1 * m2 / R2 ^ 2 = G * m1 * m2 / (3 * R1) ^ 2 = G * m1 * m2 / 9 * R1 ^ 2.
F1 / F2 = G * m1 * m2 / R1 ^ 2: G * m1 * m2 / 9 * R1 ^ 2 = 9.
Answer: with an increase in the distance by 3 times, the force of mutual attraction will decrease by 9 times: F1 / F2 = 9.