How will the force of interaction of point charges change with an increase in one charge by 6 times?

The force of interaction between charges according to Coulomb’s law:
F = k * q1 * q2 / L², where k is the coefficient 9 * 10 ^ 9, q1 is the value of the first charge, q2 is the value of the second charge, L is the distance between them.
1. Force of interaction before increasing:
F1 = k * q1 * q2 / L²
2. The force of interaction, after increasing one charge by 6 times:
F2 = k * q1 * (q2 * 6) / L²
3. Divide F2 / F1:
F2 / F1 = (k * q1 * (q2 * 6) / L²) / (k * q1 * q2 / L²) = (k * q1 * (q2 * 6) * L²) / (L² * k * q1 * q2 ) = 6
It turns out that the force of interaction has increased 6 times.
Answer: the strength of interaction has increased 6 times.