How will the internal energy of 5 g of water change when it is cooled by 10 C?

m = 5g = 0.005kg,
Δt = 10 ° С,
c = 4200J / (kg * deg);
ΔE -?
The internal energy of the water will decrease. Its change is equal to the loss of the amount of heat:
ΔE = Q = m * c * Δt = 0.005 * 4200 * 10 = 210J.

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