How will the kinetic energy of a tram change if its speed increases by K = 2 times? Decrease n = 3 times?

Kinetic energy of the tram:
Ek = (mV ^ 2) / 2, where m is the mass of the tram, V is the speed of movement.
Kinetic energy of a tram with a 2-fold increase in speed (V1 = 2V):
Ek1 = (mV1 ^ 2) / 2 = (m * (2V) ^ 2) / 2 = (4mV ^ 2) / 2.
Ek1 / Ek = ((4mV ^ 2) / 2) / ((mV ^ 2) / 2) = 4 (kinetic energy will increase 4 times).
Kinetic energy of a tram with a 3-fold decrease in speed (V2 = V / 3):
Ek2 = (mV2 ^ 2) / 2 = (m * (V / 3) ^ 2) / 2 = 1/9 * (mV ^ 2) / 2.
Ek1 / Ek = ((4mV ^ 2) / 2) / (1/9 (mV ^ 2) / 2) = 1/9 p (kinetic energy will decrease 9 times).