How will the Lorentz force acting on a proton from the side of the magnetic field

How will the Lorentz force acting on a proton from the side of the magnetic field change with a 4-fold decrease in the charge velocity and a 2-fold increase in the magnetic field induction?

Fl = q * V * B * sinα, where q is the proton charge (constant value, q = 1.6 * 10-19 C), V is the proton velocity, B is the magnetic field induction, α is the angle between the proton velocity vector and lines of magnetic induction (for this problem a constant value).

Lorentz force with a decrease in the charge speed by 4 times (V1 = 0.25V) and an increase in induction by 2 times (B1 = 2V):

Fl1 = q * V1 * B1 * sinα = q * 0.25V * 2B * sinα = 0.5 * (q * V * B * sinα) = 0.5Fl.

Answer: The Lorentz force will decrease by 2 times.