How will the magnetic field energy of the coil change if the current in it is reduced by a third?

I2 = I1 – I1 / 3 = 2 * I1 / 3.
W1 / W2 -?
The magnetic field energy of the coil is determined by the formula: W = L * I ^ 2/2.
Where L is the inductance of the coil, I is the magnitude of the current in the coil.
W1 = L * I1 ^ 2/2.
W2 = L * I2 ^ 2/2 = L * (2 * I1 / 3) ^ 2/2 = 4 * L * I1 ^ 2/18 = 2 * L * I1 ^ 2/9.
W1 / W2 = (L * I1 ^ 2/2): (2 * L * I1 ^ 2/9) = 9/4 = 2 1/2.
Answer: W1 / W2 = 2 1/2 – the energy of the magnetic field with a decrease in the current strength will also decrease 2 1/2 times.