How will the period of free electrical oscillations in the oscillatory circuit change if the inductance

How will the period of free electrical oscillations in the oscillatory circuit change if the inductance of the coil is increased by 16 times.

L2 = 16 * L1.

T2 / T1 -?

An electric oscillatory circuit is a capacitor and a coil connected in series. The period of oscillation of the pendulum T is the time of one complete oscillation.

The period of natural free oscillations T of the electric circuit is determined by the Thomson formula: T = 2 * п * √ (L * C), where п is the number pi, L is the inductance of the coil, C is the capacitance of the capacitor.

T1 = 2 * п * √ (L1 * C).

T2 = 2 * п * √ (L2 * C) = 2 * п * √ (16 * L1 * C) = 4 * 2 * п * √ (L1 * C) = 4 * T1.

T2 / T1 = 4 * T1 / T1 = 4.

Answer: the period of free electrical oscillations will increase by 4 times: T2 / T1 = 4.



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