How will the pressure change if the force is increased three times, and the area is reduced by 9 times?

The pressure that a given force exerts on a certain surface can be calculated using the formula: P = F (force) / S (area).

Initial pressure: P1 = F1 / S1.

Pressure after increasing the force by 3 times and reducing the area by 9 times: P2 = F2 / S2, where F2 = 3F1 and S2 = 1/9 S1.

Let’s perform the transformations:

P2 = 3F1 / 1/9 S1 = 3 * 9F1 / S1 = 27P1.

Answer: The pressure will increase 27 times.