How will the reaction rate of CO + Cl2 = COCl2 change if the volume is reduced by 3 times?

V = k [A] [B],

where V is the reaction rate,

k – coefficient of proportionality, l / mol s,

[A] and [B], concentration of molecules (A) or (B), mol / L.

Initially, we have:

V1 = k * [CO] [Cl2].

After volume reduction:

V2 = k * [3CO] [3Cl2];

V2 / V1 = k * [3CO] [3Cl2] / k * [CO] [Cl2] = k * 9 [CO] [Cl2] / k * [CO] [Cl2] = 9/1 = 9.

When the volume is reduced by 3 times, the reaction rate will increase by 9 times.