How will the strength of the current flowing through a wire of constant cross-section change

How will the strength of the current flowing through a wire of constant cross-section change if the voltage between its ends and the length of the wire are halved?

U2 = U1 / 2 – the voltage between the ends of the wire was halved;

l2 = l1 / 2 – the wire length was halved.

It is required to determine I2 / I1 – how will the strength of the current flowing through the wire change after all the changes.

In the first case, the current strength will be equal to:

I1 = U1 / R1 = U1 / (r * l1 / s) = U1 * s / (r * l1), where r is the resistivity of the material from which the wire is made, s is the cross-sectional area of ​​the wire.

In the second case, the current strength will be equal to:

I2 = U2 / R2 = U2 * s / (r * l2) = (U1 / 2) * s / (r * l1 / 2) = U1 * s / (r * l1).

Then:

I2 / I1 = (U1 * s / (r * l1)) / (U1 * s / (r * l1)) = 1, that is, the current will not change.

Answer: if you reduce the voltage and the length of the wire by 2 times, the current will not change.