How will the temperature of a zinc ball change when dropped from a height of 0.4 meters?

Given:
h = 0.4 m
с = 400 J / kg * С – specific heat of zinc
Emech = Q
(t2 – t1) -?
Emech = Ek + En – Emech – total mechanical energy, Ek at the initial moment of time = 0, En – potential energy at the initial moment of time is maximum
Ep = m * g * h, m is the mass of the zinc ball, g = 9.8 m / s ^ 2 is the acceleration of gravity
Q = c * m * (t2 – t1)
c * m * (t2 – t1) = m * g * h, we reduce the masses: c * (t2 – t1) = g * h
(t2 – t1) = g * h / c
(t2 – t1) = 9.8 * 0.4 / 400
(t2 – t1) = 0.01 kg = 10 g