How will the temperature of water weighing 880 g change if it is told the same amount of heat that goes
| March 5, 2021 | education
How will the temperature of water weighing 880 g change if it is told the same amount of heat that goes to heating an aluminum cylinder weighing 2 kg at 200C.
Data: m1 (mass of water) = 880 g = 0.88 kg; m2 (mass of the aluminum cylinder) = 2 kg; Δt2 (change in temperature of the aluminum cylinder) = 200 ºС.
Reference values: C1 (specific heat of water) = 4200 J / (kg * K); C2 (specific heat capacity of aluminum) = 920 J / (kg * K).
The change in water temperature is determined from the following equality: C1 * m1 * Δt1 = C2 * m2 * Δt2, whence Δt1 = C2 * m2 * Δt2 / (C1 * m1).
Calculation: Δt1 = 920 * 2 * 200 / (4200 * 0.88) ≈ 100 ºС.
Answer: The water temperature will increase by 100 ºС.
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