How will the volume of the parallelepiped change if its length is increased by 2.16, the width is reduced

How will the volume of the parallelepiped change if its length is increased by 2.16, the width is reduced by 7 1/5, and the height is increased by 2 4/21.

Consider a parallelepiped whose length is a, width b, and height c (these are its measurements). As you know, the volume of such a parallelepiped will be V = abc.

Now let’s see how its values will change. The length after an increase of 2.16 times becomes equal to 2.16a. The width after decreasing 7 1/5 times becomes equal to b: 7 1/5 = b: 36/5 = b * 5/36 = (5b) / 36. The height after increasing 2 4/21 times becomes equal to c * 2 4/21 = c * 46/21 = (46s) / 21.

Thus, the volume of the modified box will become V = 2.16a * (5b) / 36 * (46c) / 21 = 23/35 * abc.

This means that the volume will increase 23/35 times.