Hydration of propylene produced propanol weighing 40 grams. How many grams of water wasted?

Let’s write down the solution, compose the reaction equation:
С3Н6 + Н2О = С3Н7ОН – hydration reaction, propanol was obtained;
Let’s determine the molar masses of substances:
M (H2O) = 2 +16 = 18 g / mol;
M (C3H7OH) = 3 * 12 + 8 + 16 = 60 g / mol;
Let’s calculate the amount of moles of propanol:
Y (C3H7OH) = m / M = 40/60 = 0.66 mol;
Let’s make the proportion:
X mol (H2O) – 0.66 mol (C3H7OH);
-1 mol – 1 mol from here, X mol (H2O) = 1 * 0.66 / 1 = 0.66 mol;
We find the mass of water:
m (H2O) = Y * M = 0.66 * 18 = 11.88 g.
Answer: 11.88 g of water was spent to carry out the reaction.