Hydrochloric acid reacts with 195 g of zinc. How much hydrogen was generated in this case? Determine its volume.

Zinc reacts with hydrochloric acid to release hydrogen gas and form zinc chloride:

Zn + 2HCl = ZnCl2 + H2;

1 mole of zinc reacts with 2 moles of acid. In this case, 1 mol of salt is formed and 1 mol of hydrogen gas is released.

Let’s calculate the available chemical amount of zinc. To do this, divide the weight of pure metal by the weight of 1 mole of metallic zinc.

M Zn = 65 grams / mol; N Zn = 195/65 = 3 mol;

The same amount of hydrogen and zinc chloride salt will be synthesized.

Let’s calculate the volume of hydrogen. To do this, multiply the amount of substance by the volume of 1 mole of gas, which is 22.4 liters.

N H2 = 3 mol; V H2 = 3 x 22.4 = 67.2 liters;