Hydrochloric acid was added to 150 g of sodium carbonate solution until gas evolution ceased.

Hydrochloric acid was added to 150 g of sodium carbonate solution until gas evolution ceased. A total of 3.36 liters of gas were released. Calculate the mass fraction of sodium carbonate in the original solution

Given:
m solution (Na2CO3) = 150 g
V (CO2) = 3.36 l
To find:
w (Na2CO3)
Decision:
Na2CO3 + 2HCl = 2NaCl + H2O + CO2
n (CO2) = V / Vm = 3.36 l / 22.4 l / mol = 0.15 mol
n (CO2): n (Na2CO3) = 1: 1
n (Na2CO3) = 0.15 mol
m in islands (Na2CO3) = n * M = 0.15 mol * 106 g / mol = 15.9 g
w (Na2CO3) = m in-va / m p-ra = 15.9 g / 150 g = 0.106 * 100% = 10.6%
Answer: 10.6%