Hydrochloric acid was applied to a solution weighing 200 g with a mass fraction of sodium silicate

| March 5, 2021 | education

Hydrochloric acid was applied to a solution weighing 200 g with a mass fraction of sodium silicate of 6.1%. Calculate the mass of the precipitate formed.

1. Let’s write down the equation of the proceeding reaction:

Na2SiO3 + 2HCl = H2SiO3 ↓ + 2NaCl;

2. find the mass of sodium silicate:

m (Na2SiO3) = w (Na2SiO3) * m (solution) = 0.061 * 200 = 12.2 g;

3.Calculate the chemical amount of silicate:

n (Na2SiO3) = m (Na2SiO3): M (Na2SiO3);

M (Na2SiO3) = 23 * 2 + 28 + 3 * 16 = 122 g / mol;

n (Na2SiO3) = 12.2: 122 = 0.1 mol;

4.determine the amount of silicic acid precipitate:

n (H2SiO3) = n (Na2SiO3) = 0.1 mol;

5.Calculate the mass of the sediment:

m (H2SiO3) = n (H2SiO3) * M (H2SiO3);

M (H2SiO3) = 2 + 28 + 3 * 16 = 78 g / mol;

m (H2SiO3) = 0.1 * 78 = 7.8 g.

Answer: 7.8 g.



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