Hydrogen sulfide was passed through a solution of lead (II) nitrate, and 3.5 g of precipitate formed.

univerkov | November 18, 2020 | education

Hydrogen sulfide was passed through a solution of lead (II) nitrate, and 3.5 g of precipitate formed. What mass of lead nitrate was dissolved in the original solution?

Pb (NO3) 2 + H2S-2HNO3 + PbS (sediment)
n (PbS) = 3.5: 239 = 0.1mol
n (PbS) -n (Pb (NO3) 2)
0.1n-x
n (Pb (NO3) 2) = 0.1
m (Pb (NO3) 2) = 0.1 * 331 = 33.1g
Answer: 33.1 grams of lead nitrate was dissolved

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