Hydrogen was passed over the heated sulfur. The resulting gas was passed through an excess of copper (II) nitrate solution.

| February 14, 2021 | education

Hydrogen was passed over the heated sulfur. The resulting gas was passed through an excess of copper (II) nitrate solution. A precipitate with a mass of 4.12 g fell out. Calculate the volume of hydrogen reacted.

Reaction 1: S + H2 = H2S
Reaction 2: H2S + Cu (NO3) 2 = CuS + 2HNO3
The amount of CuS substance (sediment): n = m / M = 4.12 g / 96 g / mol = 0.043 mol. According to reaction 2 from 1 mol of hydrogen sulfide, 1 mol of copper sulfide is formed, and according to reaction 1, 1 mol of copper sulfide is obtained from 1 mol of hydrogen, n (CuS) = n (H2S) = n (H2) = 0.043 mol. The volume of hydrogen: V = n * Vm = 0.043 mol * 22.4 L / mol = 0.9632 L. (M – molar mass, determined by Mendeleev’s table, Vm – molar volume, constant value for all gases at normal conditions)



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