Hydrogen weighing 0.04 kg is in a vessel with a volume of 8.3 m ^ 3 at a temperature of 300 K.
| April 6, 2021 | education
Hydrogen weighing 0.04 kg is in a vessel with a volume of 8.3 m ^ 3 at a temperature of 300 K. The hydrogen pressure in the vessel is …
To find the value of the hydrogen pressure in the indicated vessel, we use the formula: P = m * R * T / (V * MH2).
Constants and variables: m is the mass of hydrogen (m = 0.04 kg); R – universal gas constant (R = 8.314 J / (K * mol)); T is the hydrogen temperature (T = 300 K); V is the volume of the indicated vessel (V = 8.3 m3); MH2 – molar mass (MH2 = 2 * 10 ^ -3 kg).
Calculation: P = m * R * T / (V * MH2) = 0.04 * 8.314 * 300 / (8.3 * 2 * 10 ^ -3) = 6.01 * 10 ^ 3 Pa.
Answer: The hydrogen pressure in the indicated vessel is 6.01 kPa.
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