Hydrogen with a mass of 4 g was passed by heating over 20 g of copper oxide 2.

Hydrogen with a mass of 4 g was passed by heating over 20 g of copper oxide 2. What mass of metallic copper can be obtained in this case?

Divalent copper oxide is reduced with hydrogen gas when heated. This synthesizes metallic copper and water. This reaction is described by the following equation:

CuO + H2 = Cu + H2O;

Cupric oxide reacts with hydrogen in equal molar amounts. When the reaction proceeds, the same equal chemical amounts of copper and water are synthesized.

Let’s determine the chemical amount of hydrogen.

M H2 = 2 grams / mol;

m H2 = 4 grams;

N H2 = 4/2 = 2 mol;

Let’s calculate the chemical (molar) amount of copper oxide.

M CuO = 64 + 16 = 80 grams / mol;

m CuO = 20 grams;

N CuO = 20/80 = 0.25 mol;

Thus, hydrogen is taken in excess.

During the reaction, 0.25 mol of copper oxide can be reduced to obtain 0.25 mol of copper.

Its mass will be equal to:

M Cu = 64 grams / mol;

m Cu = 64 x 0.25 = 16 grams;