Hydrogen with a volume of 5.6 liters was passed while heating over copper oxide (2), determine the amount

Hydrogen with a volume of 5.6 liters was passed while heating over copper oxide (2), determine the amount of substance and the mass of the resulting water.

CuO + H2 = Cu + H2O.

It is known that 1 mole of gas at normal conditions. takes up a volume of 22.4 liters. Then you can find the amount of hydrogen substance in this problem:

n = 5.6 / 22.4 = 0.25 mol.

Because from 1 mole of hydrogen 1 mole of water is formed, then from 0.25 mole of hydrogen 0.25 mole of water is formed. Found amount of water substance:

n = 0.25 mol. From here you can find the mass of water:

m = Mr * n = 18 * 0.25 = 4.5 g.