Hydrogen with a volume of 72 liters reacted with nitrogen. The ammonia yield is 85%. Calculate the mass of the ammonia obtained.
February 15, 2021 | education
| Hydrogen with a volume of 72 liters reacted with nitrogen. The ammonia yield is 85%. Calculate the mass of the ammonia obtained.
Given:
VH2 = 72 l
vNH3 = 85%
72L x
N2 + 3 H2 = 2 NH3
1 mol 3 mol 2 mol
nH2: n NH3 = 3: 2
m NH3 -?
n = V / V mol. , where Vmol. = 22.4 liters the volume of one mole of any gas (molar volume).
nH2 = 72 / 22.4 = 3.2 mol,
Accordingly, n NH3 = 3.2 / 3 * 2 = 2.1 mol
m = M * n, where M is the molar mass of ammonia
MNH3 = 14 + 3 = 17 g / mol
Respectively
m NH3 = 2.1 * 17 = 36.3 g. mass of ammonia according to the reaction equation (theoretical yield).
v = (mn / mtot.) * 100%
Otsuda
m clean = v * mtot. / one hundred%
m NH3 = 85% * 36.3 / 100% = 30.9g.
Answer: 30.9 grams is the mass of the ammonia obtained.
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