Hydrogenation of ethylene with a volume of 22 liters yielded 20 liters of ethane. Calculate the volume

Hydrogenation of ethylene with a volume of 22 liters yielded 20 liters of ethane. Calculate the volume fraction of the ethane yield.

To solve the problem, we compose an equation according to the condition:
V = 22 HP V = 20 HP
1. С2Н4 + Н2 = С2Н6 – hydrogenation reaction, ethane was obtained;
1 mol 1 mol.
2. Let’s calculate the number of moles of ethylene, ethane, applying Avogadro’s law:
1 mol of gas at normal level – 22.4 liters;
X mol (C2H4) – 22 liters. hence, X mol (C2H4) = 1 * 22 / 22.4 = 0.982 mol;
Y (C2H4) = 0.982 mol since the amount of these substances is equal to 1 mol according to the equation.
3. Find the theoretical volume of ethane:
V (C2H6) = 0.982 * 22.4 = 21.99 l.
4. Let’s calculate the volume fraction of the reaction product yield:
V (practical) / V (theoretical) * 100 = 20 / 21.99 * 100 = 90.95%
Answer: Ethane was obtained, the volume fraction of which is 90.95%.




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