Hydrolysis of 70 g of aluminum carbide Al4C3 formed methane CH4 and aluminum hydroxide Al (OH) 3
| December 6, 2020 | education
Hydrolysis of 70 g of aluminum carbide Al4C3 formed methane CH4 and aluminum hydroxide Al (OH) 3 calculate the volume of methane formed
Al4C3 + 12H2O = 4Al (OH) 3 + 3CH4
M (Al4C3) = 144 g / mol
n = 70/144 = 0.49 mol
Methane is produced 3 times more, i.e.
0.49 * 3 = 1.47 mol
V (CH4) = Vm * n = 22.4 * 1.47 = 32.928 L
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