Hypertension in humans is determined by a dominant autosomal gene, and optical atrophy is caused

Hypertension in humans is determined by a dominant autosomal gene, and optical atrophy is caused by a recessive gene linked to a spol. A woman with optic atrophy marries a man with hypertension, whose father also suffered from hypertension, and the mother was healthy. What is the probability that a child in this family will suffer from both anomalies, in%? What is the probability of having a healthy baby, in%?

Let’s designate the gene that causes the development of hypertension in humans as K, then the gene that causes the absence of a tendency to develop this disease will be designated as k.

Let’s designate the chromosome with the optic atrophy gene as Xg, then the chromosome with the gene that determines the well-being of a person in relation to this vision pathology will be designated as XG.

A woman with optical atrophy has the kkXgXg genotype. It produces one type of egg – kXg.

The man’s mother did not suffer from hypertension, therefore, she possessed the kk genotype homozygous for the recessive trait and could transfer only the recessive k gene to the man.

Thus, a man with hypertension is heterozygous for this trait. It has the Kk XGY genotype and produces four types of spermatozoa – K XG, kY, KY, k XG.

The offspring of this married couple are represented by the following hypothetically possible options:

girls with a predisposition to hypertension (Kk XGXg) – 25%;

boys with optical atrophy (kkXg Y) – 25%;

boys with optic atrophy and predisposition to hypertension (Kk XgY) – 25%;

healthy girls (kk XGXg) – 25%.

Answer: the probability of having a child with both considered health anomalies is 25%; the probability of having a healthy baby is 25%.