Ice floated in the water. what mass of ice melted if 0.25 MJ of heat was reported to this system?

Since there is no change in the state of this system, its temperature is 0 ºС and the mass of melted ice is determined by the formula: Q = λl * m, from where we express: m = Q / λl.

Const: λl – beats. heat of melting of ice (λl = 3.3 * 10 ^ 5 J / kg).

Data: Q – supplied heat (Q = 0.25 MJ = 2.5 * 10 ^ 5 J).

Let’s calculate: m = Q / λl = 2.5 * 10 ^ 5 / (3.3 * 10 ^ 5) ≈ 0.758 kg.

Answer: Ice weighing 758 g should have melted.