Ice weighing 500 g was heated from -20 degrees to the melting point. How much heat was transferred to the ice?

The amount of heat that was transferred to the ice when heated:

Q = C * m * (tc – tn), where C is the specific heat capacity of ice (tabular value C = 2100 J / (K * kg)), m is the specified mass of heated ice (m = 500 g = 0.5 kg) , tc – ice melting temperature (tc = 0 ºС), tн – ice temperature in the initial state (tн = -20 ºС).

Let’s calculate:

Q = C * m * (tc – tn) = 2100 * 0.5 * (0 – (-20)) = 2100 * 0.5 * 20 = 21000 J = 21 kJ.

Answer: Heat was transferred to ice in the amount of 21 kJ.