Identical metal balls, charged with charges q1 = -3q, q2 = 7q, brought into contact and

Identical metal balls, charged with charges q1 = -3q, q2 = 7q, brought into contact and moved apart to the same place, and then brought into contact the second and third balls with a charge q3 = -6q. Each of the balls will have a charge

Consider the interaction of the first and second balls. The total charge Q will be:

Q = q1 + q2 = -3q + 7q = + 4q.

After diluting them, it will split between the balls:

q1 = q2 = Q / 2.

q1 = q2 = 4q / 2 = + 2q.

We consider the interaction of the second and third balls in a similar way:

Q = q2 + q3 = 2q – 6q = -4q.

q2 = q3 = Q / 2;

q2 = q3 = -4q / 2 = -2q.

Answer: after interactions, the magnitudes of the charges will be q1 = 2q, q2 = -2q, q3 = -2q.