If 6s after the beginning of the movement the body travels a path of 27m, then what is the acceleration of the body?

Task data: t (time of movement of a given body) = 6 s; S (distance traveled) = 27 m; V0 (initial speed) = 0 m / s.

The acceleration with which a given body began to move can be expressed from the formula: S = V0 * t + a * t: 2/2 = 0 + a * t: 2/2, whence a = 2S / t: 2.

Let’s make a calculation: a = 2 * 27/6: 2 = 54/36 = 1.5 m / s2.

Answer: The required acceleration of a given body was equal to 1.5 m / s2.