If a brown-eyed left-handed man heterozygous for the first allele married a blue-eyed woman with a better

If a brown-eyed left-handed man heterozygous for the first allele married a blue-eyed woman with a better right hand than the left (heterozygous for the second trait), what is the phenotype to be expected in their children?

Let’s designate the gene responsible for the development of brown eyes in humans as K, and the gene responsible for the development of blue eyes as k.

Let’s designate the gene for left-handedness as l, and the gene for predominant right-handedness as L.

A left-handed male heterozygous for eye color will be recorded as Kkll. It will produce two types of sperm – Kl and kl.

A blue-eyed, right-handed woman, heterozygous for the second trait, will be recorded as kkLl. This woman will produce two types of eggs – kL and kl.

The likely offspring of a given married couple will include the following options:

right-handed children with brown eyes (KkLl) – 25%;

right-handed children with blue eyes (kkLl) – 25%;

left-handed children with brown eyes (Kkll) – 25%;

left-handed children with blue eyes (kkll) – 25%.